AD8130ARM-REEL3_集成电路资料查询网

rev. 0
ad8129/ad8130
–8–
频率
–
MHz
增益
–
dB
3
1 300
10 100
0
–
3
–
4
–
5
–
6
–
7
–
2
–
1
1
2
V
输出
= 0.3v p-p
V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 19. 一个d8129 频率 response
vs. 供应, v
输出
= 0.3 v p-p
频率
–
MHz
增益
–
dB
4
1 300
10 100
1
–
2
–
3
–
4
–
5
–
6
–
1
0
2
3
V
S
=

5V
C
L
= 20pf
C
L
= 10pf
C
L
= 5pf
C
L
= 2pf
tpc 22. AD8129 频率 response
vs. 加载 电容
频率
–
MHz
增益
–
dB
3
10
2
1
0
–
1
–
2
–
3
–
4
–
5
–
6
–
7
100 300
R
L
= 150

V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 25. AD8129 频率 response
vs. 供应, r
L
= 150
Ω
频率
–
MHz
增益
–
dB
3
1 300
10 100
0
–
3
–
4
–
5
–
6
–
7
–
2
–
1
1
2
V
输出
= 1v p-p
V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 20. ad8129 频率 回馈
vs. 供应, v
输出
= 1 v p-p
频率
–
MHz
增益
–
dB
0.5
1 300
10 100
0.2
–
0.1
–
0.2
–
0.3
–
0.4
–
0.5
0
0.1
0.3
0.4
R
L
= 1k

V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 23. ad8129 fine 规模 回馈
vs. 供应, r
L
= 1 k
Ω
频率
–
MHz
增益
–
dB
3
1 300
10 100
0
–
3
–
4
–
5
–
6
–
7
–
2
–
1
1
2
g = 20
V
输出
= 0.3v p-p
V
S
=

2.5v
V
S
=

5v,

12V
tpc 26. AD8129频率 response
vs. 供应, g = 20, v
输出
= 0.3 v p-p
频率
–
MHz
增益
–
dB
3
1 300
10 100
0
–
3
–
4
–
5
–
6
–
7
–
2
–
1
1
2
V
输出
= 2v p-p
V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 21. ad8129 频率 回馈
vs. 供应, v
输出
= 2 v p-p
频率
–
MHz
增益
–
dB
0.3
1 300
10 100
0
–
0.3
–
0.4
–
0.5
–
0.6
–
0.7
–
0.2
–
0.1
0.1
0.2
R
L
= 150

V
S
=

2.5v
V
S
=

5V
V
S
=

12V
tpc 24. ad8129 fine 规模 回馈
vs. 供应, r
L
= 150
Ω
频率
–
MHz
增益
–
dB
3
1 300
10 100
0
–
3
–
4
–
5
–
6
–
7
–
2
–
1
1
2
g = 20
V
输出
= 2v p-p
V
S
=

5v,

12V
V
S
=

2.5v
tpc 27. AD8129频率 response
vs. 供应, g = 20, v
输出
= 2 v p-p
ad8129 频率 回馈 特性
(g = 10, r
L
= 1 k

, c
L
= 2 pf, v
输出
= 0.3 v p-p, t
一个
= 25

c, 除非 否则 指出.)

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rev. 0 ad8129/ad8130 –8– 频率 – MHz 增益 – dB 3 1 300 10 100 0 – 3 – 4 – 5 – 6 – 7 – 2 – 1 1 2 V 输出 = 0.3v p-p V S =  2.5v V S =  5V V S =  12V tpc 19. 一个d8129 频率 response vs. 供应, v 输出 = 0.3 v p-p 频率 – MHz 增益 – dB 4 1 300 10 100 1 – 2 – 3 – 4 – 5 – 6 – 1 0 2 3 V S =  5V C L = 20pf C L = 10pf C L = 5pf C L = 2pf tpc 22. AD8129 频率 response vs. 加载电容频率 – MHz 增益 – dB 3 10 2 1 0 – 1 – 2 – 3 – 4 – 5 – 6 – 7 100 300 R L = 150  V S =  2.5v V S =  5V V S =  12V tpc 25. AD8129 频率 response vs. 供应, r L = 150 Ω 频率 – MHz 增益 – dB 3 1 300 10 100 0 – 3 – 4 – 5 – 6 – 7 – 2 – 1 1 2 V 输出 = 1v p-p V S =  2.5v V S =  5V V S =  12V tpc 20. ad8129 频率回馈 vs. 供应, v 输出 = 1 v p-p 频率 – MHz 增益 – dB 0.5 1 300 10 100 0.2 – 0.1 – 0.2 – 0.3 – 0.4 – 0.5 0 0.1 0.3 0.4 R L = 1k  V S =  2.5v V S =  5V V S =  12V tpc 23. ad8129 fine 规模回馈 vs. 供应, r L = 1 k Ω 频率 – MHz 增益 – dB 3 1 300 10 100 0 – 3 – 4 – 5 – 6 – 7 – 2 – 1 1 2 g = 20 V 输出 = 0.3v p-p V S =  2.5v V S =  5v,  12V tpc 26. AD8129频率 response vs. 供应, g = 20, v 输出 = 0.3 v p-p 频率 – MHz 增益 – dB 3 1 300 10 100 0 – 3 – 4 – 5 – 6 – 7 – 2 – 1 1 2 V 输出 = 2v p-p V S =  2.5v V S =  5V V S =  12V tpc 21. ad8129 频率回馈 vs. 供应, v 输出 = 2 v p-p 频率 – MHz 增益 – dB 0.3 1 300 10 100 0 – 0.3 – 0.4 – 0.5 – 0.6 – 0.7 – 0.2 – 0.1 0.1 0.2 R L = 150  V S =  2.5v V S =  5V V S =  12V tpc 24. ad8129 fine 规模回馈 vs. 供应, r L = 150 Ω 频率 – MHz 增益 – dB 3 1 300 10 100 0 – 3 – 4 – 5 – 6 – 7 – 2 – 1 1 2 g = 20 V 输出 = 2v p-p V S =  5v,  12V V S =  2.5v tpc 27. AD8129频率 response vs. 供应, g = 20, v 输出 = 2 v p-p ad8129 频率回馈特性 (g = 10, r L = 1 k  , c L = 2 pf, v 输出 = 0.3 v p-p, t 一个 = 25  c, 除非否则指出.)

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