典型 characteristics–ad8005
–5–
rev. 一个
频率 – mhz
1 50010 100
1
5
3
2
0
–1
–2
–3
–4
–5
4
g = +1
normalized 增益 – db
V
S
=
5V
V
输出
= 200mv p-p
R
L
= 1k
g = +2
g = +10
R
F
= 499
图示 4. 频率 回馈; g = +1, +2, +10; v
S
=
±
5 v
频率 – mhz
0.1
5.9
6.2
6.1
6.0
5.8
5.7
5.6
5.5
5.4
5.2
5.3
50010 1001
增益 – db
g = +2
V
输出
= 200mv p-p
R
L
= 1k
图示 5. 增益 flatness; g = +2; v
S
=
±
5 v 或者 +5 v
频率 – mhz
1 50010 100
4
–1
6
5
3
2
1
0
–2
7
增益 – db
V
S
=
5V
V
输出
= 4v p-p
V
S
=
5V
V
输出
= 2v p-p
图示 6. 大 信号 频率 回馈;
g = +2, r
L
= 1 k
Ω
频率 – mhz
1 50010 100
4
–4
–3
5
3
2
1
0
–5
–2
–1
g = –1
R
F
= 1.5k
normalized 增益 – db
V
S
=
5V
V
输出
= 200mv p-p
R
L
= 1k
g = –10
R
F
= 1k
图示 7. 频率 回馈; g = –1, –10; v
S
=
±
5 v
阶段
频率 – hz
120
100
0
60
40
20
80
140
1k 100M10k 100k 1M 10M 1G
–40
–80
–280
–160
–200
–240
–120
0
阶段 – degrees
增益
增益 – db
图示 8. transimpedance 增益 和 阶段 vs. 频率
频率 – mhz
0.5 100110
9
1
2
10
8
7
6
5
0
3
4
顶峰-至-顶峰 输出 电压
(
1%thd) – 伏特
V
S
= +5v
g = +2
R
L
= 1k
图示 9. 输出 摆动 vs. 频率; v
S
=
±
5 v
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